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3494. Find the Minimum Amount of Time to Brew Potions

LeetCodeArraySimulationPrefix SumOpen on judge ↗

You are given two integer arrays, skill and mana, of length n and m, respectively. In a laboratory, n wizards must brew m potions in order. Each potion has a mana capacity mana[j] and must pass through all the wizards sequentially to be brewed properly. The time taken by the ith wizard on the jth potion is timeij = skill[i] * mana[j]. Since the brewing process is delicate, a potion must be passe

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solution.cppC++17

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