2293. Min Max Game

LeetCodeArraySimulationOpen on judge ↗

You are given a 0-indexed integer array nums whose length is a power of 2. Apply the following algorithm on nums: - Let n be the length of nums. If n == 1, end the process. Otherwise, create a new 0-indexed integer array newNums of length n / 2. - For every even index i where 0 <= i < n / 2, assign the value of newNums[i] as min(nums[2 * i], nums[2 * i + 1]). - For every odd index i where 0 <=

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solution.cppC++17

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