Counting Graphs

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Let $G$ be a simple connected undirected graph with $N$ vertices. Consider the following pseudocode, that produces one DFS order of $G$: ```cpp mark = [0, ..., 0] is an array of length N+1 filled with zeros order = [] is an empty array function DFS(v): append v to order mark[v] = 1 for x in 1..n: if x is adjacent to v and mark[x] == 0: DFS(x) DFS(1) ``` Quite simply, this is a depth-

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solution.cppC++17

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