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The powerful sum

CodeChefRating 1977Open on judge ↗

Let us calculate the sum of k-th powers of natural numbers from 1 to n. As the result can be quite large, output the result modulo some integer p. Input First tOutput For each test case, output the value: (1k+2k+...+nk) mod p. ### Sample Test Cases **Sample 1** Input: ``` 4 10 1 1000000 10 2 1000000 10 3 1000000 10 4 1000000 ``` Output: ``` 55 385 3025 25333 ```

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solution.cppC++17

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