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Last Digit Sum

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For a non-negative integer N, define S(N) as the sum of the odd digits of N plus twice the sum of the even digits of N. For example, S(5)=5, S(456)=2*4+5+2*6=25, and S(314159)=3+1+2*4+1+5+9=27. Define D(N) as the last digit of S(N). So D(5)=5, D(456)=5, and D(314159)=7. Given 2 non-negative integers A and B, compute the sum of D(N) over all N between A and B, inclusive. Input Input will begin wi

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solution.cppC++17

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