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Mean Difference (Easy)

CodeChefRating 1792Open on judge ↗

*This is the easy version of the problem. The only difference between this and the hard version is that here, you must find the answer for only the given array.* For an array $B$ of length $M$, we define the following: - $\text{avg}(B)$ is the *average* of $B$, rounded down. Formally, $\displaystyle\text{avg}(B) = \left\lfloor\frac{B_1 + B_2 + \ldots + B_M}{M}\right\rfloor$ where $\left\lfl

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solution.cppC++17

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